IE interview, the difference between two number is four and the difference their square is 48. what is the largest one?
the difference between two number is four and the difference their square is 48. what is the largest one? the difference between two number is four and the difference their square is 48. what is the largest one? Let the two numbers be and , where . We are given two conditions: 1. The difference between the two numbers is 4: X-Y=4 2. The difference between their squares is 48: X²-Y²=48 Using the identity , we can substitute :X²-Y²=(x-y)(x+y),we can substitute x-y=4 (x - y)(x + y) = 48 4(x + y) = 48 ] x + y = 12 Now we have the system of two equations: 1. X-Y=4 2. X+Y=12 We can solve this system by adding the two equations: (x - y) + (x + y) = 4 + 12 2x = 16 ] x = 8 Substitute x=8 into x+y=12 8 + y = 12 y = 4 ] Thus, the two numbers are 8 and 4, and the largest one is 8.